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Totally bounded space - Wikipedia
WebNov 20, 2024 · C. Goffman asserts that "… in a metric space X a set S is compact if and only if it is closed and totally bounded." [1] and "… every totally bounded sequence in a metric space has convergent subsequence." [2]. The statements (incidentally, equivalent to each other) are both wrong, as the following counter-example shows. Take the set of all ... WebAug 1, 2024 · Solution 1. Assume that ( x n) n ∈ N is a Cauchy sequence in a sequentially compact space X. Introduce a convergent subsequence ( x n k) k ∈ N of ( x n) with x n k → x. Let ϵ > 0 be given. Choose N such that ρ ( x i, x j) < ϵ / 2, i, j ≥ N. Choose n k > N such that ρ ( x n k, x) < ϵ / 2. Then we have. proving completeness. riverland aboriginal
Math 396. Handout on compactness criteria - Stanford University
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